Loads - Scenario 1
 
SITUATION   An induction motor, rated 240 Volts, draws a current of 150 Amps and brings the system power factor down to 70.7%. What capacitor size is needed to raise system power factor to 95%?        ANALYSIS   1.) Complex power equations, vector:   S-> = P-> + Q->  S<a = P + jQ  S<a = S cos(a) + j S sin(a)   2.) System power factor angle:   P = S cos(a)  pf = P/S = cos(a) = 0.707  a = arccos(0.707) = 45deg   3.) Motor apparent power, scalar:   S = Vi = 240V * 150A = 36kVA   4.) Motor real and reactive power:   P,load = S cos(a)  P,load = 36k cos(45) = 25,455.84W   Q,load = S sin(a)  Q,load = 36k sin(45) = 25,455.84VAr   5.) System power factor angle after capacitor correction:   pf = cos(a) = 0.95  a = arccos(0.95) = 18.19deg   6.) Real power, unaffected:   P,load = 25,455.84W   7.) Desired system apparent power:   P = S cos(a)  25,455.84 = S cos(18.19)  S = 25,455.84 / cos(18.19)  S = 26,794.87VA   8.) Desired system reactive power:   Q,sys = S sin(a)  Q,sys = 26,794....

 
