Electrical Design Analysis

Consider this generator again from the previous scenario , but this time, with half of its rated capacity attached. This post examines what will happen to its internal EMF at half-load condition. SITUATION A compound DC generator rated 20 kiloWatts, with resistances in its armature winding at 0.05 ohm, series field winding at 0.025 ohm, and shunt field winding at 100 ohms, operates at HALF LOAD with 250 Volts at its terminals. With the machine configured as short shunt, what is the internal electromotive force produced by the generator? ANALYSIS 1.) Schematic diagram, short shunt compound: 2.) One-line diagram: o|---EMF---R,ar---|---R,se---V,L---|> | R,sh | v 3.) Power drawn by load: P,L = 10kW (HALF LOAD) 4.) Voltage at the generator terminals: V,t = 250V 5.) Resistances 5.1.) Armature winding resistance: R,ar = 0.05 ohm 5.2.) Series field winding resistance: R,se = 0.025 ohm 5.3.) S

Consider the generator from the previous scenario , but without any loads attached. This post examines what will happen to its internal EMF at no-load condition. SITUATION A compound DC generator rated 20 kiloWatts, with resistances in its armature winding at 0.05 ohm, series field winding at 0.025 ohm, and shunt field winding at 100 ohms, operates at NO LOAD with 250 Volts at its terminals. With the machine configured as short shunt, what is the internal electromotive force produced by the generator? ANALYSIS 1.) Schematic diagram, short shunt compound: 2.) One-line diagram: o|---EMF---R,ar---|---R,se---V,t---x | R,sh | v 3.) Power drawn by load: P,L = 0 (NO LOAD) 4.) Voltage at the generator terminals: V,t = 250V 5.) Resistances 5.1.) Armature winding resistance: R,ar = 0.05 ohm 5.2.) Series field winding resistance: R,se = 0.025 ohm 5.3.) Shunt field winding resistance: R,sh = 100 oh

SITUATION A compound DC generator rated 20 kiloWatts, with resistances in its armature winding at 0.05 ohm, series field winding at 0.025 ohm, and shunt field winding at 100 ohms, operates at full load with 250 Volts at its terminals. With the machine configured as short shunt, what is the internal electromotive force produced by the generator? ANALYSIS 1.) Schematic diagram, short shunt compound: 2.) One-line diagram: o|---EMF---R,ar---|---R,se---V,L---|> | R,sh | v 3.) Power drawn by load: P,L = 20kW (full load) 4.) Voltage at the generator terminals: V,t = 250V 5.) Resistances 5.1.) Armature winding resistance: R,ar = 0.05 ohm 5.2.) Series field winding resistance: R,se = 0.025 ohm 5.3.) Shunt field winding resistance: R,sh = 100 ohms 6.) Short shunt configuration 6.1.) Load current is same as series field current: i,L = i,se 6.2.) Load voltage is same as generator terminal vol